\"\"

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The system of linear equations are

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\"\"                                             (Equation 1)

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\"\"                                      (Equation 2)

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\"\"                                            (Equation 3)

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The leading of coefficient of the first equation is one, you can begin by saving the x at the upper left and eliminating the other x - terms from the first column.So, adding negative one times the first equation to the second equation produces a new second equation.

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\"\"\"\"

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So, the new system of equations are

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\"\"                                            (Equation 1)

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\"\"                                           (Equation 2)

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\"\"                                            (Equation 3)

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Now that all but the first x have been eliminated from the first column, go to back on the second column.(You need to eliminate y from the third equation.)So, adding second equation to the third equation produces a new third equation.

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\"\"\"\"

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So the new system of equations are

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\"\"                                            (Equation 1)

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\"\"                                           (Equation 2)

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\"\"                                                    (Equation 3)

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Finally, you need a coefficient of 1 for y in the second equation and coefficient of 1 for z in the third equation, so multiply the second equation by \"\" produces a new second equation and so multiply the third equation by \"\" produces a new third equation respectively.The new system in row - echelon form of equations are

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\"\"                                            (Equation 1)

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\"\"                                             (Equation 2)

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\"\"                                                        (Equation 3)\"\"

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To solve for y, the value of \"\" substitute in equation 2 to obtain as follows:

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\"\"                                         (Substitute \"\")

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\"\"                                            (Add 3 to each side)

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\"\"                                                     (Apply LCM rule: \"\")

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To solve for x, the values of \"\" substitute in equation 1 to obtain as follows:

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\"\"                                        (Substitute \"\")

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\"\"                                        (Subtract \"\" from each side)

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\"\"                                              (Simplify)

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\"\"                                                    (Apply LCM rule: \"\")

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The solution is \"\", which can be write as the ordered triple \"\".\"\"

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The solution is \"\".