$\"\"$

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The system of linear equations are

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$\"\"$ (Equation 1)

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$\"\"$ (Equation 2)

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The leading of coefficient of the first equation is one, you can begin by saving the x at the upper left and eliminating the other x - terms from the first column.So, adding negative five times the first equation to the second equation produces a new second equation.

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$\"\"$ $\"\"$

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So, the new system of equations are

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$\"\"$ (Equation 1)

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$\"\"$ (Equation 2)

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Multiplying the second equation to the third equation by $\"\"$ produces a new second equation.

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So, the new system of equations are

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$\"\"$ (Equation 1)

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$\"\"$ (Equation 2) $\"\"$

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In the second equation, solve for y in terms of z to obtain $\"\"$ .

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By back - substituting $\"\"$ into equation 1, you can solve for x, as follows:

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$\"\"$ (Write equation 1)

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$\"\"$ (Substitute $\"\"$ )

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$\"\"$ (Simplify)

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$\"\"$ (Subtract $\"\"$ from each side)

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Finally let $\"\"$ , where a is a real number, the solutions of the system $\"\"$ . $\"\"$

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The solution in ordered triple form is $\"\"$ .