(a)
\The equation is and the point is
.
To tell the ordered pair is a solution, substitute the values of
in the original equation.
.
The above statement is true.So the point is a solution of the equation
, and \ \
The point is lies on the graph of
.
(b)
\The equation is and the point is
.
To check the solution, substitute the values of in the original equation.
.
The above statement is false.So the point is not a solution of the equation
, and \ \
The point does not lies on the graph of
.
(a) The point is lies on the graph of
.
(b) The point does not lies on the graph of
.