(a)
\The equation is and the point is
.
To check the solution, substitute the values of in the original equation.
.
Since the above statement is true, the point is a solution of the equatio
, and
The point lies on the graph of
.
(b)
\The equation is and the point is
.
To check the solution, substitute the value of in the original equation.
.
Since the above statement is false, the point is not a solution of the equation
, and
The point does not lies on the graph of
.
(a) The point lies on the graph of
.
(b) The point does not lies on the graph of
.