\
The equation for cross-section is .
(a)
\Find the intercepts.
\Find the -intercept by substituting
in the equation.
-intercept is
.
Find the -intercept by substituting
in the equation
.
Since the solutions are imaginary, there is no -intercept.
Intercept is.
\
(b)
\Test algebraically symmetric with respect to the -axis:
Substitute for
in
.
Because is equivalent to
, the graph is symmetric with respect to the
-axis.
\
Test algebraically symmetric with respect to the -axis:
Substitute for
in
.
Because is not equivalent to
, the graph is not symmetric with respect to the
-axis.
\
\
Test algebraically symmetric with respect to the origin:
\Substitute for
and
for
in
.
Because is not equivalent to
, the graph is not symmetric with respect to the origin.
(a) Intercept is.
(b) -axis symmetry.