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For instance the equation is \"\".

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Check the symmetry of \"\":

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Test algebraically symmetric with respect the \"\"-axis:

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Substitute \"\" for \"\" in \"\".

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\"\"

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\"\"

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Because \"\" is equivalent to \"\", the graph is symmetric with respect to the \"\"-axis.

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Test algebraically symmetric with respect to the \"\"-axis:

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Substitute \"\" for \"\" in \"\".

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\"\"

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\"\"

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Because \"\" is equivalent to \"\", the graph is symmetric with respect to the \"\"-axis.

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Test algebraically symmetric with respect to the origin:

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Substitute \"\" for \"\" and \"\" for \"\" in \"\".

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\"\"

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\"\"

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Because \"\" is equivalent to \"\", the graph is symmetric with respect to the origin.

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Symmetry about the \"\"-axis is \"\".

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Symmetry about the \"\"-axis is \"\".

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Symmetry about the origin \"\".

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Case 1:

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If the point \"\" is on the graph of the equation.

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If the equation is symmetric with respect to the \"\"-axis and \"\"-axis:

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Then \"\" and \"\" are passes through the graph.

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Thus, \"\" are passes through the graph.

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This is the origin symmetry.

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Case 2:

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If the point \"\" is on the graph of the equation.

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If the equation is symmetric with respect to the \"\"-axis and origin:

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Then \"\" and \"\" are passes through the graph.

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Thus, \"\" are passes through the graph.

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This is the \"\"-axis symmetry.

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Case 3:

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If the point \"\" is on the graph of the equation.

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If the equation is symmetric with respect to the \"\"-axis and origin:

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Then \"\" and \"\" are passes through the graph.

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Thus, \"\" are passes through the graph.

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This is the \"\"-axis symmetry.

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Thus, if two symmetries are present, the remaining one must also be present.

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\"\"

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If two symmetries are present, the remaining one must also be present.