$\"\"$

The rational function is $\"\"$ .

In rational functions the denonator can not be zero.

Find exceptional values equate denominator to zero.

$\"\"$

The domain of function $\"\"$ is $\"\"$ .

$\"\"$ .

$\"\"$ is in lowest terms.

The rational function is $\"\"$ .

Change $\"\"$ to $\"\"$ .

$\"\"$ .

Find the intercepts.

Find $\"\"$ -intercept equate numerator to $\"\"$ .

$\"\"$

The $\"\"$ - intercept is at $\"\"$ .

Find the $\"\"$ -intercept by substituting $\"\"$ $\"\"$ in the rational function.

$\"\"$ .

The $\"\"$ -intercept is $\"\"$ .

Find the vertical asymptote by equating denominator to zero.

$\"\"$

So the function has vertical asymptote at $\"\"$ and $\"\"$ .

Graph:

Graph the function with its vertical asymptotes.

$\"\"$

Find horizontal asymptote, first find the degree of the numerator and

degree of the denominator.

Degree of the numerator $\"\"$ and degree of the denominator is $\"\"$ .

Oblique asymptote:

If the degree of the numerator is grater than the degree of denominator

then oblique asymptote exist.

Thus, the function has no oblique asymptote.

$\"\"$

There are no zeros in the numerator.

The zeros of denominator are $\"\"$ ,use these values to divide the $\"\"$ -axis

into three intervals are $\"\"$ .

$\"\"$

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