The rational function is .
The domain of a rational function is the set of all real numbers except those for which the denominator is .
Find which number make the fraction undefined create an equation where the denominator is not equal to .
The domain of the is the set of all real numbers
except
.
The domain of function is
.
.
is in lowest terms is
.
The rational function is .
Change to
.
.
Find the intercepts.
\Find the -intercept by equating
to zero.
Find the -intercept by substituting
in the rational function.
-intercept is
and
-intercept is
.
Find the vertical asymptote by equating denominator to zero.
\The function has vertical asymptote at .
To find horizontal asymptote, first find the degree of the numerator and degree of the denominator.
\Degree of the numerator is and degree of the denominator is
.
Since the degree of the numerator is equal to the degree of the denominator, horizontal asymptote is the ratio of leading coefficient of numerator and denominator.
\Leading coefficient of numerator is , leading coefficient of denominator is
.
is horizontal asymptote.
The function has horizontal asymptote at .
The zero of the numerator is ; the zero of denominator is
, use these values to divide the
-axis into three intervals.
.
Interval | \ \
\ | \
\
\ | \
\
\ | \
\
Number chosen \ | \
\
| \
\
| \
\
| \
\
Value of | \
\
| \
\
| \
\
| \
\
Location of graph \ | \
\
Above | \
\
Below | \
\
Above | \
\
Point of graph \ | \
\
| \
\
| \
\
| \
Behavior of the graph :
\ and
, hence the graph of
is will approach the vertical asymptote, at
.
and
, hence the graph of
is will approach the horizontal asymptote, at
.
Graph :
\The graph of :
First determine the intervals of , such that the graph is below the
-axis from the graph.
The graph of the function is above the
-axis on the intervals
.
From the graph, for
.
The solution set is or in interval notation,
.
;
.