\"\"

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The rational function is \"\".

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The domain of a rational function is the set of all real numbers except those for which the denominator is \"\".

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Find which number make the fraction undefined create an equation where the denominator is not equal to \"\" .

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\"\"

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The domain of the \"\" is the set of all real numbers \"\" except \"\".

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The domain of function \"\" is \"\".

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The rational function is \"\".

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\"\"

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\"\" is in lowest terms.

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The rational function is \"\".

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Change \"\" to \"\".

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\"\".

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Find the intercepts.

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Find the \"\"-intercept by equating \"\" to zero.

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\"\"

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\"\"

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Find the \"\"-intercept by substituting \"\"\"\" in the rational function.

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\"\"

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\"\"

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\"\"-intercept is \"\", \"\"-intercept is\"\".

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Determine the behavior of the graph of \"\" near each \"\"-intercept.

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Near \"\" : \"\".

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Plot the point \"\" and indicate a line with negative slope.

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Find the vertical asymptote by equating denominator to zero.

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\"\"

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The function has vertical asymptote at \"\".

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To find horizontal asymptote, first find the degree of the numerator and degree of the denominator.

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Degree of the numerator is \"\" and degree of the denominator is \"\".

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Since the degree of the numerator is equal to the degree of the denominator, horizontal asymptote is the ratio of leading coefficient of numerator and denominator.

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Leading coefficient of numerator is \"\" , leading coefficient of denominator is \"\" .

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\"\" is horizontal asymptote.

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The function has horizontal asymptote at \"\".

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\"\"

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The zero of the numerator is \"\" ;the zero of denominator is \"\",use these values to divide the

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\"\"-axis into three intervals.

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\"\" and \"\".

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\"\"

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Interval \

\"\"

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  \"\"

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 \"\"

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Number chosen

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\"\"

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\"\"

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\"\"

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Value of \"\"

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\"\"

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\"\"

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\"\"

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Location of graph

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Above \"\"-axis

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Below  \"\"-axis

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Below \"\"-axis

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Point of graph

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\"\"

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\"\"

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\"\"

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\"\"

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 End behavior of the graph:

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 \"\" and \"\", hence the graph of \"\" approaches to a vertical asymptote at \"\".

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As \"\", hence the graph of \"\" approaches to a horizontal asymptote at \"\". \ \

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\"\"

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Graph :

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The graph of \"\":

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\"\"

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\"\"

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First determine the intervals of \"\", such that the graph is above the \"\"-axis and where \"\" from the graph.

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The graph of the function \"\" is above the \"\"-axis and \"\" on the intervals \"\".

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From the graph, \"\" for \"\" or \"\".

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The solution set is \"\" or in interval notation, \"\".

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\"\"

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\"\"; \"\".