$\"\"$

The inequality is $\"\"$ .

Step 1: Determine the real zeros ( $\"\"$ -intercepts of the graph )of $\"\"$ and the real numbers for which $\"\"$ is undefined.

The zeroes of the function are the values of $\"\"$ for which $\"\"$ .

THe function is $\"\"$ .

The zeroes of $\"\"$ are $\"\"$ .

A rational function is undefined when denominator is zero.

$\"\"$ is undefined for $\"\"$ and $\"\"$ .

$\"\"$

Step 2: Use the zeros and undefined values found in Step 1 to divide the real number line into intervals.

Denominator of the function should not be zero.

$\"\"$ and $\"\"$

$\"\"$ and $\"\"$ .

The function is defined for all values of $\"\"$ except at $\"\"$ and $\"\"$ .

The function intervals are $\"\"$ .

$\"\"$

Step 3: Select a number in each interval, evaluate $\"\"$ at the number, and determine whether $\"\"$ is positive or negative.

If $\"\"$ is positive, all values of $\"\"$ in the interval are positive. If $\"\"$ is negative, all values of $\"\"$ in the interval are negative.

$\"\"$ .

The real zero of numerator is $\"\"$ and the real zeros of denominator $\"\"$ and $\"\"$ .

So the real zeros are divide the $\"\"$ - axis into three intervals.

$\"\"$

The function intervals are $\"\"$ .

Choosing a number for $\"\"$ in each interval and evaluating $\"\"$ .

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\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \

Interval	\ $\"\"$ \	\ \ $\"\"$ \	Conclusion
\ $\"\"$ \	\ $\"\"$ \	\ $\"\"$ \	Positive
\ $\"\"$ \	\ $\"\"$ \	\ \ $\"\"$ \	Positive
\ $\"\"$ \	\ $\"\"$ \	\ \ \ \ \ $\"\"$ \ \	Negative
\ $\"\"$ \	\ $\"\"$ \	\ $\"\"$ \	Positive

The solution of the inequality $\"\"$ in set notation is $\"\"$ .

The solution of the inequality $\"\"$ in interval notation is $\"\"$ .

$\"\"$ ; $\"\"$ .