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Given function

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Let y = x+1

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dy = dx

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Let z = √(y-3) ⇒ y = z²+3

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dz =[1 / (2√(y-3)) ] dy

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dz = (1/2z)dy

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dy = 2zdz

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Substitute : z = √(y-3)

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Substitute : y = x+1

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