\"\"

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The functions are \"\" and \"\".

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(a)

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Solve \"\".

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Substitute \"\".

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\"\"

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Apply logarithm one to one property : if \"\",then \"\".

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\"\"

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\"\"

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\"\".

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Therfore,the solution is \"\".

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The solution set is \"\".

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The point is on the graph of \"\" is \"\".

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\"\"

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(b)

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Solve \"\".

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Substitute \"\".

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\"\"

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Apply logarithm one to one property : if \"\",then \"\".

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\"\"

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\"\"

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\"\"

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\"\"

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Therefore,the solution is \"\".

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The solution set is \"\".

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The point is on the graph of \"\" is \"\".

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\"\"

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(c)

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Solve for \"\".

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Equate \"\" and \"\".

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\"\"

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Apply logarithm one to one property : if \"\",then \"\".

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\"\"

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\"\"

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\"\"

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\"\"

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Therefore, the solution is \"\".

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The solution set is \"\"

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Substitute \"\" in \"\".

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\"\"

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\"\"

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\"\"

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\"\"

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Therefore,the point is \"\".

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Yes, the graphs of the functions \"\" and \"\" intersect at the point \"\".

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\"\"

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(d)

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Solve for \"\".

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\"\".

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Substitute \"\" and \"\".

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\"\"

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Apply logarithm product property : \"\".

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\"\"

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Apply logarithm one to one property : if \"\",then \"\".

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\"\"

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\"\"

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\"\"

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\"\"

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Solve for \"\" by factorizing the quadratic equation.

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\"\"

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\"\"

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\"\"

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Apply zero product rule.

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\"\" or \"\"

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\"\" or \"\"

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Since \"\" does not exist, hence it is not considered.

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Therefore, the solution is \"\".

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The solution set is \"\".

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\"\"

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(e)

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Solve for \"\".

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\"\"

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Substitute \"\" and \"\".

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\"\"

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Apply logarithm quotient property : \"\".

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\"\"

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Apply logarithm one to one property : if \"\",then \"\".

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\"\"

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Solve for \"\".

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\"\"

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\"\"

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\"\"

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\"\"

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\"\"

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Therefore,the solution is \"\".

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The solution set is \"\".

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\"\"

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(a) The solution set is \"\" and the point is on the graph of \"\" is \"\".

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(b) The solution set is \"\" and the point is on the graph of \"\" is \"\".

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(c) The solution set is \"\".

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   Yes,the grpahs of the functions \"\" and \"\" are intersected at the point \"\".

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(d) The solution set is \"\".

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(e) The solution set is \"\".