Area of the sector , where
is the radius of the circle and
is the central angle.
Find the angle rotated by the sprinkler.
\Area covered by the water sprinkler square yards.
Radius of the circle yd.
Consider .
Substitue and
in above formula.
Thus, the angle rotated by the sprinkler is 0.89 radian.
\ \The angle rotated by the sprinkler is 0.89 radian.