\
(a)
\Find .
The trigonometric function .
The value of is
.
Therefore, the point is on the graph of
.
\
(b)
\If the function is defined as a list of ordered pairs, simply swap the and
values.
Remember, the inverse relation will be a function only if the original function is one-to-one.
\The point is on the graph of
.
Since the function is one-to-one, the point
is on the graph of
.
\
(c)
\Find the value of at
.
The function is .
Substitute in above function.
(since the trigonometric function
)
Therefore, the point is on the graph of
.
\
(a)
\The value of is
.
Therefore, the point is on the graph of
.
(b)
\The point is on the graph of
.
(c)
\The point is on the graph of
.