(a)
\The function .
Find the -intercept:
Consider .
Find the -intercept, by substituting
in
.
.
The -intercept is
.
(b)
\Find for what numbers the graph of is decreasing in the interval is
.
The function .
Apply derivative on each side with respect to .
Determination of critical points :
\The critical points exist when .
Equate to zero:
Solve in the interval
.
General solution of is
, where
is an integer.
General solution is
If ,
.
If ,
.
If ,
The solutions are ,
and
in the interval
.
The critical points are ,
and
and the test intervals are
.
Interval | \Test Value | \Sign of ![]() | \
Conclusion | \
![]() | \
![]() | \
\
| \
Increasing | \
![]() | \
![]() | \
\
| \
Decreasing | \
The function is Decreasing over the interval .
(c)
\The function and the interval is
.
The critical points are and
and
.
\
Find the values of at these critical points.
.
.
.
Compare the values of to find the absolute minimum.
Absolute minimum value is .
(d)
\The function and the interval is
.
General solution of is
, where
is an integer.
General solution: .
If ,
.
If ,
.
If ,
.
The solutions are and
in the interval
.
(e)
\The function and the interval is
.
General solution of is
, where
is an integer.
General solution: .
If ,
.
If ,
.
If ,
.
The solutions are ,
and
in the interval
.
General solution of is
, where
is an integer.
General solution: .
If ,
.
If ,
.
The solutions are and
in the interval
.
(f)
\General solution of is
, where
is an integer.
General solution: .
If ,
.
If ,
.
If ,
.
The solutions are in the interval
.
(g)
\ Find the -intercept :
The function .
Find the -intercept, by substituting
in
.
General solution of is
, where
is an integer.
The -intercepts are
, where
is an integer.
(a). The -intercept is
.
(b).The function is Decreasing over the interval .
(c). Absolute minimum value is .
(d).The solutions are and
in the interval
.
(e). For ,the solutions are
,
and
in the interval
For , the solutions are
and
in the interval
.
(f). The solutions are in the interval
.
(g).The -intercepts are
, where
is an integer.