Find .
The function .
The point is on the circle
.
Compare the equation with .
Radius of the circle .
Substitute and
in the above equation.
Since the point lies on third quadrant, the value of .
The point is on a circle of radius
.
From the figure, angle lies in third quadrant.
.
Double-angle identity : .
Apply the formula : .
Substitute ,
and
in
.
Substitute in
.
Therefore, .
.