![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step1.JPG\")
The polar equation is ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=dd05f0f8b3532a559318ed4b57cce49d.png\")
.
Convert the polar equation to a rectangular equation.
\
Squaring on each side.
\![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=6392812750d6bb2420b3cb0a7720cfd3.png\")
Substitute ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=d55f84a8f76478ca8b0bee3fa1055e8b.png\")
.
![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=4571410cae3acc4d380e2cb7b70d4ff7.png\")
.
The equation in rectangular form is .
The equation is in the form of standard circle equation ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=df309fbf2ead06d6cc234b7ee60a83ee.png\")
with center ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=82a2e3157032d22284bb9f309b45242e.png\")
and .
Observe the graphs:
\The graph (E) is a circle with radius and center ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=705611204d558ceea79e29c7658a4bfc.png\")
.
The graph (E) is correct choice.
\![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")
The graph (E) is correct choice.