\"\"

\

Center = (h,k) = (2,-3) \ \

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a = 4 \ \

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Vertices are \ \

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V1 = (h-a , k)  = (2-4 , \"minus\"3) = (-2,-3) \ \

\

V2 = (h-a , k) = (2+4, \"minus\"3) = (6,-3)

\

\"\"

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The solution is " (\"minus\"2, \"minus\"3) ; (6, \"minus\"3) ".