\
The cross-sectional area of a beam is , where
is the length in feet of half the base of the beam.
(a)
\Find the domain of .
Since it is radical function, radicand should be greater than or equals to zero.
\The domain is .
\
(b)
\Graph the function :
.
\
(c)
\Make a table of values to find ordered pairs that satisfy the function.
\Choose values for and find the corresponding values for
.
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
\
| \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
Observe the above table of values :
\The value of maximizes the cross-sectional area.
Thus, the length of the base of the beam to maximize the cross-sectional area is feet.
(a) The domain is .
(b)
\Graph of the function is :
\
(c)
\The value of maximizes the cross-sectional area.
The length of the base of the beam to maximize the cross-sectional area is feet.