\
The function is .
Where, is objects weight(in pounds).
is objects weighs(in pounds) at sea level.
is height of the object above sea level.
(a)
\If Amy weighs 120 pounds at sea level, how much will she weigh on Pikes Peak, which is 14,110 feet above sea level.
\Amy weighs pounds.
.
.
Thus, the height of the object above sea level miles.
Consider .
Substitute corresponding values in above function.
\Thus, Amy weigh is 119.84 lbs.
\\
(b)
\Use a graphing utility graph the function .
Here Amy weighs pounds.
Substitute the above value in the function.
\.
Graph of the function is :
\
(c)
\Create a table.
\Choose values for and find the corresponding values for
.
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
Observe the above table :
\As changes from 0 to 5 miles, the weight
varies 0.03.
\
(d)
\Find At what height will Amy weigh 119.95 pounds.
\Consider .
From the given data :
\At 0.8 miles Amy weigh will 119.95 pounds.
\\
(e)
\Yes, the answer to part (d) seem to be reasonable.
\Because observe the above table :
\At the height mile, weight is 119.94 pounds and,
At the height mile, weight is 119.97 pounds.
From answer (d) :
\At 0.8 miles Amy weigh will 119.95 pounds.
\0.8 is between 0.5 and 1, and
\119.95 is between 119.97 and 119.94.
\So, the answer to part (d) seem to be reasonable.
\ \(a) Amy weigh is 119.84 lbs.
\(b)
\Graph of the function is :
(c) As changes from 0 to 5 miles, the weight
varies 0.03.
(d) At 0.8 miles Amy weigh will 119.95 pounds.
\(e) The answer to part (d) seem to be reasonable.