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n( AUB ) = 60, n( A∩B ) = 40 and n(A) = n(B). \ \

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By using counting formula : n( AUB ) = n(A) + n(B) n( A∩B ) \ \

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Substitute : n( AUB ) = 60 , n( A∩B ) = 40. \ \

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60 = n(A) + n(B) − 40 \ \

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Substitute n(A) = n(B) \ \

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60 = n(A) + n(A) − 40 \ \

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60 = 2n(A− 40 \ \

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2n(A) = 40 + 60 \ \

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\"\"                 (Divide each side by 2)

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n(A) = 50

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n(A) = 50