The equation is and the point is
.
Consider .
Differentiate on each side with respect to .
Slope of the tangent line at .
Slope of the tangent line is .
Point slope form of line equation is .
Substitute and
in the above equation.
Tangent line is .
The slope of the tangent line is perpendicular to the normal line slope.
\slope of tangent line*slope of normal line is equal to .
Point slope form of line equation is .
Substitute and
in the above equation.
Normal line equation is .
The equation of circle with center and radius between these two circles
is
.
Differentiate on each side with respect to .
Substitute .
Substitute in the above equation.
Substitute in the circle equation
Circle passes through the point .
Roots of the quadratic equation is .
Then,
\Therefore and
.
Substitute in
.
Substitute in
.
.
Circle equations are and
.
Graph:
\Graph both the circle equations, curve, tangent line, normal line and point.
\Tangent line equation is .
Normal line equation is .
Circle equations are and
.