\"\"

\

The equation is \"\" and points are \"\" and \"\".

\

The equation is \"\".

\

Apply derivative on each side with respect to \"\".

\

\"\"

\

\"\".

\

\"\".

\

Consider the point \"\".

\

The derivative of the equation \"\" at the point \"\" is the slope of the line.

\

\"\".

\

The line equation is \"\".

\

Substitute \"\" and \"\" in the line equation.

\

\"\"

\

The tangent line equation is \"\".

\

\"\"

\

Normal line is perpendicular to tangent line then,

\

slope of tangent line \"\" slope of normal line is equal to\"\" .

\

Let slope of the normal as \"\".

\

Therefore, \"\".

\

\"\".

\

point slope form of line equation is \"\".

\

Substitute \"\" and \"\" in the above equation.

\

\"\"

\

The normal line equation is \"\".

\

\"\"

\

The equation is \"\".

\

Apply derivative on each side with respect to \"\".

\

\"\"

\

\"\".

\

\"\".

\

Consider the point \"\".

\

The derivative of the equation \"\" at the point \"\" is the slope of the line.

\

\"\".

\

The line equation is \"\".

\

Substitute \"\" and \"\" in the line equation.

\

\"\"

\

\"\"

\

The tangent line is \"\".

\

\"\"

\

Normal line is perpendicular to tangent line then,

\

slope of tangent line \"\" slope of normal line is equal to\"\" .

\

Let slope of the normal as \"\".

\

Therefore, \"\"

\

\"\".

\

point slope form of line equation is \"\".

\

Substitute \"\" and \"\" in the above equation.

\

\"\"

\

\"\"

\

 The normal line equation is  \"\".

\

\"\"

\

 

\

Graph:

\

Graph the conic equation \"\".

\

Graph the tangent line equations \"\" and \"\".

\

Graph the normal line equations  \"\" and \"\".

\

\"\"

\

\"\"

\

A the point \"\" :

\

The tangent line equation is \"\".

\

The normal line equation is \"\".

\

As the point \"\" :

\

The tangent line is \"\".

\

 The normal line equation is  \"\".

\

Graph:

\

Graph of the conic equation \"\", the tangent line equations \"\" and \"\" and the normal line equations  \"\" and \"\" is

\

\"\".