The function is $\"f(x)=cos$ and the interval is $\"\\left$ .

$\"f(x)=cos$

Apply derivative on each side with respect to $\"x\"$ .

$\"\\\\$

To find the critical numbers of $\"f(x)\"$ , equate $\"f\'(x)\"$ to zero.

$\"\\\\f\'(x)=0\\\\$

For $\"n=0\"$

$\"x=0\"$ .

The function $\"f(x)\"$ has critical value at $\"x=0\"$ .

$\"x=0\"$ is in the region $\"\\left$ .

$\"\\\\f(0)=cos$

To find the absolute extreme of function in given region $\"\\left$ , sketch the function .

$\"\"$

Critical point $\"(0,\\$ is maximum point over the interval $\"\\left$ .

Right end point $\"\\left$ is minimum point over the interval $\"\\left$ .

$\"\"$

Minimum point is $\"\\left$ .

Maximum point is $\"(0,\\$ .