The function is $\"g(x)=\\sec$ and the interval is $\"\\left$ .

$\"g(x)=\\sec$

Apply derivative on each side with respect to $\"x\"$ .

$\"\\\\$

To find the critical numbers of $\"g(x)\"$ , equate $\"g\'(x)\"$ to zero.

$\"\\\\g\'(x)=0\\\\$

For $\"n=0\"$

$\"\\\\\\$ .

$\"x=0\"$ is in the region $\"\\left$ .

$\"\\\\g(0)=\\sec$

To find the absolute extreme of function in given region $\"\\left$ , sketch the function .

$\"\"$

Critical point $\"(0,\\$ is minimum point over the interval $\"\\left$ .

Right end point $\"\\left$ is maximum point over the interval $\"\\left$ .

$\"\"$

Minimum point is $\"(0,\\$ .

Maximum point is $\"\\left$ .