\"\"

\

The function is \"f.

\

\"fraction                     (Apply derivative with respect to x)

\

\"f                       (The sum rule)

\

\"f                                    (\"fraction

\

\"\"

\

To find the critical point then f\\'(x) = 0

\

\"f

\

\"2

\

\"c

\

 

\

\"c

\

\"x                         (The critical number)

\

\"\"

\

Because there are no points for which f\\' does not exist. you can conclude that \"x and \"x are the only critical numbers. The table summarizes the testing of the three intervals determined by two critical numbers.

\

 

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
\

Interval

\
\

\"\"

\
\

\"fraction

\
\

\"fraction

\
\

Test Value

\
\

\"x

\
\

\"x

\
\

\"x

\
\

Sign of f\\'(x)

\
\

\"f

\
\

\"f

\
\

\"f

\
\

Conclusion

\
\

Increasing

\
\

Decreasing

\
\

Increasing

\
\

By applying the First Derivative Test, you can conclude that f  has one relative minimum at the point \"open and another at the point \"open

\

\"\"

\

Therefore Relative minimum: \"open

\

Relative maxmum: \"open.