The function is and intervals are
.
Find the intercepts :
\To find the - intercept, substitute
in the function.
Solve in the interval
.
doesnot exist for real values of
.
The solutions of to
in the interval
.
Therefore, the - intercepts are
to
.
To find the -intercept, substitute
in the function.
The - intercept is
.
Find the relative extrema for the function
Consider .
Differentiate on each side with respect to .
.
.
To find the critical numbers, equate to
.
.
.
There is no solution for in the interval
.
Thus, the critical points occur at to
.
If , then
.
If , then
.
The relative maximum is .
The relative minimum is .
Find the points of inflection
\Consider .
Differentiate on each side with respect to .
.
Apply .
The second derivative of is
.
Equate to
.
.
The inflection points occurs at .
Substitute in the function.
.
The inflection points occurs at and
.
Relative extrema points exist at critical numbers, Then intervals are and
.
Perform first derivative test to identify the nature of the extrema.
\Test itervals | \Test value | \Sign of ![]() | \
Conclusion | \
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\
| \
Relative minimum | \
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\
| \
Relative minimum | \
No relative extrema point.
\Find asymptote of function .
To find horizontal asymptote .
.
.
There is no horizontal asymptote.
\To find vertical asymptote,denominator of the function is equated to zero.
\The function is defined for all values of .
There is no vertical asymptote.
\Graph :
\Graph the function .
Observe the graph ,
\The relative maximum is .
The relative minimum is .
The inflection points occurs at and
.
There is no horizontal and vertical asymptote.
\The relative maximum is .
The relative minimum is .
The inflection points occurs at and
.
There is no horizontal and vertical asymptote.
\Graph the function .