(a)
\Observe the figure :
\Consider the first rectangular solid.
\Dimensions of the first rectangular solid are ,
and
inches.
Surface area of the rectangular solid is .
Substitute corresponding values in the above formula.
\Therefore, surface area of the solid is sq.inches.
Consider the second regular cube.
\Side of the cube is inches.
Surface area of the cube is .
Substitute in the above formula.
.
Therefore, surface area of the cube is sq.inches.
Consider the third rectangular solid.
\Dimensions of the first rectangular solid are ,
and
inches.
Surface area of the rectangular solid is .
Substitute corresponding values in the above formula.
\Therefore, surface area of the solid is sq.inches.
Hence it is verified that the each of the solid has a surface area of sq.inches.
(b)
\Volume of the first rectangular solid is .
Substitute ,
and
in above formula.
Volume of the first rectangular solid is cubic inches.
\
Volume of the second regular cube is .
Substitute in the above formula.
Volume of the cube is cubic inches.
\
Volume of the third rectangular solid is .
Substitute ,
and
in above formula.
Volume of the third rectangular solid is cubic inches.
(c)
\Surface area of the rectangular solid is .
If the base is square then .
Surface area of the rectangular solid with square base is
\Surface area of the rectangular solids with square base is sq.inches.
Substitute in
.
Volume of the rectangular cube with square base is .
Substitute in
.
Apply derivative on each side with respective to .
For maximum volume equate to zero . \ \
.
Substitute in
.
Therefore, dimensions of the rectangular solids with square base are ,
and
.
(a) Verified that the each of the solid has a surface area of sq.inches.
(b) Volume of the first rectangular solid is cubic inches.
Volume of the cube is cubic inches.
Volume of the third rectangular solid is cubic inches.
(c) Dimensions of the rectangular solids with square base are ,
and
.