Let be the length of the rectangle and
be the width of the rectangle.
Area of the rectangle .
Find in terms of
.
Perimeter of the rectangle .
.
.
Substitute in
.
.
.
Differentiate on each side with respect to .
Find the critical numbers by equating derivative to zero.
\Substitute in
.
.
Since the second derivative of is negative, it gives a maximum.
is maximum when
and
.
There are no dimensions that yield a minimum area.
\Explanation:
\This can be made by arbitrary small by selecting .
is maximum when
and
.
There are no dimensions that yield a minimum area.
\Explanation:
\This can be made by arbitrary small by selecting .