The right circular cylinder is designed to hold soft drink of .
(a)
\Complete the table:
\Cross section area of isosceles trapezoid is .
Where
\ and
are bases of isosceles trapezoid.
is height of isosceles trapezoid.
Base ![]() | \
Base ![]() | \
Altitude | \Area | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
(b)
\Draw a coordinate plane.
\Graph the cross-sectional area :
Using table feature of the graphing utility, complete the table:
\Angle ![]() | \
Area | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
Observe the table:
\The maximum cross-sectional area is at
.
(c)
\Find cross-sectional area of isosceles trapezoid.
\The cross-sectional area of isosceles trapezoid is .
The cross-sectional area is Where
.
(d)
\The cross-sectional area is .
Differentiate with respect to .
Equate to zero.
and
.
and
.
The critical points are and
.
At .
Second derivative the critical point is negative so it is maximum.
At .
Therefore, the maximum exist at .
(e)
\Observe the graph:
\The maximum cross-sectional area is at
.
(a)
\Base ![]() | \
Base ![]() | \
Altitude | \Area | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
\
(b)
\Angle ![]() | \
Area | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
\
The maximum cross-sectional area is at
.
(c)
\The cross sectional area is Where
.
(d)
\The maximum occurs at .
(e)
\The maximum cross-sectional area is at
.