$\"\"$

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The function is $\"integral$

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Let $\"f$

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$\"f$

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$\"f$

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The maximum value of $\"open$ on the interval [3, 5] is $\"f$

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$\"open$

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Where (a, b) = (3, 5) and $\"f$

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$\"increment$

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$\"\"$

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$\"x$

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$\"x$

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$\"x$

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$\"x$

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$\"x$

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$\"\"$

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$\"f$

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$\"f$

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$\"f$

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$\"f$

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$\"f$

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$\"\"$

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$\"integral$ (Simpson\\'s)

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$\"integral$

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$\"almost$

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$\"Syntax$

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$\"\"$

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Therefore $\"integral$ .

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