\"\"

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The function is \"integral

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Let \"f

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Find the second derivative of f. \ \

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\"f

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\"f

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\"\"

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The maximum value of \"open on the interval [0, 1] is \"f. \ \

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\"open                   (Error in the trapezoidal rule)

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\"open

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To obtain an earror E that is less than 0.00001, you must choose n such that

\

 

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\"fraction \ \

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\"begin

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\"begin

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\"begin

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\"\"

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Solving the problem using \"begin will be cumbersome. So, to make problem easy consider the error value less than or equal to 0.01

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\"open                   (Error in the trapezoidal rule)

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\"open

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To obtain an earror E that is less than 0.01, you must choose n such that

\

 

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\"fraction \ \

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\"begin

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\"begin

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\"begin

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So, you can choose n = 4. and apply the Trapezoidal rule. \ \

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\"f

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Where (a, b) = (0, 1) and \"f

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\"increment

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\"\"

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\"x

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\"x

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\"x

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\"x

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\"x

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\"\"

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\"f

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\"f

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\"f

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\"f

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\"f

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\"\"

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\"integral   (Simpson\\'s)

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\"integral

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\"almost

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\"almost \ \

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\"\"

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Therefore \"integral.