The function is .

Apply derivative on each side with respect to .

From the fundamental theorem of calculus part 1:

If is continuous on , then the function defined by is continuous on  and differentiable on  , and  .

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Therefore the derivative function is always positive.

Thus, the function is strictly monotonic and it is an one to one function.

Find .

From theorem 5.9:

.

Equate to .

Integral property: .

From the above property we will get .

Therefore, .

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Consider .

Substitute in .

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