The function is .
Consider .
The value of lies in the interval
.
.
The point does not lie on the graph
with domain
.
It does not contradict to the definition of the inverse trigonometric function.
\ is not a one-to-one function over its complete domain.
Therefore to find its inverse, restrict the domain over the interval where it is one-to-one.
Domain of is
and range is
.
does not belong to the range
.
No, the point do not lie on the graph
.
It does not contradict to the definition of the inverse trigonometric function.