$\"\"$

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The function is $\"\"$ and the interval is $\"\"$ .

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Take natural logarithm on each side.

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$\"\"$

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$\"\"$

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$\"\"$

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Differentiate with respect to $\"\"$ .

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$\"\"$

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$\"\"$

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$\"\"$ .

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$\"\"$

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The line equation passes through the point $\"\"$ .

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$\"\"$

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Slope of the tangent line is $\"\"$ .

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The point-slope form of line equation is $\"\"$ .

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Substitute the point $\"\"$ and $\"\"$ in above equation.

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$\"\"$

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Therefore, the tangent line equation is $\"\"$ .

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$\"\"$

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The tangent line equation is $\"\"$ .