The differential equation is .
The general solution is .
Initial conditions:
\ and
when
.
Consider .
Differentiate with respect to .
The first derivative is .
Differentiate with respect to .
Substitute the values of in
.
Therefore, the differential equation condition is satisfied.
\To find out the particular solution substitute in
.
Consider the general solution .
Substitute in the general solution.
The particular solution is .
Quotient rule of logarithm: .
.
The particular solution is .