The equations are ,
,
and
.
The length of the beam is .
The volume of the beam is .
The area of the beam is .
Substitute and
in
.
Substitute .
Apply derivative on each side with respect to .
.
If and
.
Substitute and
in
.
Substitute and
.
Therefore, the volume of the beam is
Find the weight of the beam.
\The density of the concrete is
The weight of the beam is .
Substitute corresponding values.
\Therefore, the weight of the beam is
(b)
\Find the centroid of the cross section of the beam.
\The centroid of the beam is .
The beam is symmetric about -axis, hence the value of the
.
The value of .
Substitute .
.
The value of
.
Apply formula : .
Substitute and
in
.
.
Therefore, the centroid of the beam is .
(a) The volume of the beam is and the weight of the beam is
(b) The centroid of the beam is .