The integral is .
.
If is continuous on the interval
then
is convergent.
Solve the integral by using integration by parts of integration.
\Apply integration by parts formula .
Consider
Apply derivative on each side with respect to .
.
Consider .
Apply integral on each side.
\.
Apply the limits.
\Apply L hospital rule:
\Therefore, the integral converges to
.
The improper integral converges to
.