The integral is .
is discontinuous at
.
If is continuous on the interval
, except for some
in
at which
has an infinite discontinuity, then
.
The improper integral on the left diverges if either of the improper integrals on the right diverges. \ \
\.
.
Apply formula: .
.
.
Therefore, the series is converges to .
Graph:
\Graph the integrand .
Observe the graph:
\Integration capabilities: .
The improper integral is converges to
.