\"\"

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Consider \"\" and \"\".

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Direct comparision test :

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If \"\" for all \"\".

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1. If \"\" converges, then \"\" converges.

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2. If \"\" diverges, then \"\" diverges.

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By comparision test, prove that \"\".

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Find the value of \"\" so that \"\".

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Consider function \"\".

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\"\", when \"\".

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\"\" for \"\".

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Therefore, \"\", \"\".

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\"\" for \"\".

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\"\" for \"\".

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Therefore, \"\".

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\"\"

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Consider \"\".

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The series \"\" is converges by \"\"-series test.

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Since \"\" is converges, by comparision test \"\" is converges.

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\"\"

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The statement is proved.