The function is .
(a)
\Find the geometric power series of the function
\The series is in the form of geometric series.
\The general form of geometric series is .
Substitute and
.
The series is converges when .
.
Therefore, the power series is and is converges in the interval
.
(b)
\Solve the series by long division method.
\The function is .
The series is .
The power series is and is converges in the interval
.