$\"\"$

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The function is $\"\"$ on the interval $\"\"$ .

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The function is $\"\"$ is continuous on the closed interval $\"\"$ .

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Intermediate value theorem:

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If $\"\"$ is continuous on the closed interval $\"\"$ , $\"\"$ , and $\"\"$ is any number between $\"\"$ and $\"\"$ , then there is at least one number in $\"\"$ such that $\"\"$ .

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Substitute $\"\"$ in $\"\"$ .

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$\"\"$ .

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Substitute $\"\"$ in $\"\"$ .

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$\"\"$ .

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$\"\"$ .

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$\"\"$ and $\"\"$ .

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$\"\"$ between $\"\"$ and $\"\"$ .

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By the intermediate theorem to state that there must be some $\"\"$ in $\"\"$ such that $\"\"$ . $\"\"$

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Find the value of $\"\"$ .

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$\"\"$ .

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$\"\"$

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Apply zero product property.

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$\"\"$ or $\"\"$ .

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$\"\"$ is out of interval [0, 3] , hence $\"\"$ .

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$\"\"$

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$\"\"$ .

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