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The mass of a particle is $\"m=\\frac{m_{0}}^{\\sqrt{1-\\frac{v^{2}}{c^{2}}}}\"$ .

Where $\"m_{0}\"$ is mass of a particle at rest and $\"c\"$ is velocity of light.

Find the limit of the mass as $\"v\"$ approaches $\"c^{-}\"$ .

$\"\\lim_{v\\rightarrow$ .

As $\"v\"$ tends to $\"c\"$ from the left side, then the fraction $\"\\frac{v^2}{c^2}\"$ becomes $\"1\"$ .

The denominator of the mass of a particle is zero, so $\"m\"$ approaches to $\"\\infty\"$ .

$\"\\lim_{v\\rightarrow$ .

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$\"\\lim_{v\\rightarrow$ .