The integral is and vertices of the triangle are
.
(a)
\The integral is .
Graph :
\(1) Draw the coordinate plane.
\(2) Plot the vertices .
(3) Connect the plotted vertices to a smooth triangle.
\Use .
Consider .
Observe the graph, the curve is bounded from
.
Here coordinates are equal then the line is parallel to
axis.
Since , then
.
The limits of x are varying from 0 to 1.
\.
Consider .
Observe the graph, the curve is bounded from
.
Here coordinates are equal then the line is parallel to
axis.
Since , then
.
The limits of y are varying from 0 to 2.
\.
Consider .
Observe the graph, The curve is bonded from .
Using two points form of a line equation is .
Substitute in the line equation.
.
The limits of x is varying from 1 to 0.
\Substitute in
.
.
From .
.
(b)
\The integral is and vertices of the triangle are
.
Greens theorem :
\If C be a positively oriented closed curve, and R be the region bounded by C, M and N are the partial derivatives on an open region then
\.
Graph :
\(1) Draw the coordinate plane.
\(2) Plot the vertices .
(3) Connect the plotted vertices to a smooth triangle.
\Observe the graph :
\The limits of x are varying from 0 to 1 , so .
Find the bounds for y :
\Lower limit :
\Consider the points .
Here coordinates are equal then the equation of the line parallel to
axis.
So the equation of the line is .
Lower limit of y is .
Upper limit :
\Consider the points .
Using two points form of a line equation is .
Substitute in the line equation.
Upper limit of y is .
The limits of y is to
, so
.
Using greens theorem,
\The region bounded by the triangle is .
.
.