The equation of elliptical region is and the point on edge of the shadow is
.
Observe the graph.
\The edge of the shadow is tangent to the curve.
\Slope of the tangent is derivative of the curve.
\Consider equation of ellipse .
Differentiate on each side with respect to .
.
Assume that the ellipse has the tangent at the point .
Slope of the tangent at .
.
Point-slope form of line equation: .
Substitute and
in the above formula.
.
The above line passes through the point .
So it will satisfy the above tangent line equation.
\The point lies on ellipse.
Therefore we have, .
Substitute in
.
.
.
Substitute in
.
Thus the points are and
.
The lamp is located in positive - axis direction, so we consider the point
only.
Slope of the tangent at is
.
Point-slope form of line equation: .
Substitute and
in the point-slope formula.
From the graph, it is observe that lamp is located 3-units right from the -axis.
And assume that lamp is located units above
-axis.
Thus the coordinates of the point at which lamp is located are .
The tangent line passes through the point
.
Hence it will satisfy the line equation.
\Therefore, the lamp is situated 2 units above the -axis.
The lamp is situated 2 units above the -axis.