\"\"

\

The equation of elliptical region is   \"\" and the point on edge of the shadow is\"\".

\

Observe the graph.

\

The edge of the shadow is tangent to the curve.

\

Slope of the tangent is derivative of the curve.

\

Consider equation of ellipse \"\".

\

Differentiate on each side with respect to \"\".

\

\"\"

\

\"\"

\

\"\"

\

\"\"

\

\"\".

\

Assume that the ellipse has the tangent at the point \"\".

\

Slope of the tangent at \"\".

\

\"\".

\

\"\"

\

Point-slope form of line equation: \"\".

\

Substitute \"\" and \"\" in  the above formula.

\

\"\".

\

The above line passes through the point \"\".

\

So it will satisfy the above tangent line equation.

\

\"\"

\

\"\"

\

The point \"\" lies on ellipse.

\

Therefore we have, \"\".

\

Substitute \"\" in \"\".

\

\"\".

\

\"\".

\

Substitute \"\" in \"\".

\

\"\"

\

Thus the points are \"\" and \"\".

\

The lamp is located in positive \"\"- axis direction, so we consider the point  \"\" only.

\

\"\"

\

Slope of the tangent at  \"\" is \"\".

\

Point-slope form of line equation: \"\".

\

Substitute \"\" and \"\" in  the point-slope formula.

\

\"\"

\

From the graph, it is observe that lamp is located 3-units right from the \"\"-axis.

\

And assume that lamp is located \"\" units above \"\"-axis.

\

Thus the coordinates of the point at which lamp is located are \"\".

\

The tangent line \"\" passes through the point \"\".

\

Hence it will satisfy the line equation.

\

\"\"

\

Therefore, the lamp is situated 2 units above the \"\"-axis.

\

\"\"

\

The lamp is situated 2 units above the \"\"-axis.

\