\"\"

\

The function is \"\".

\

Differentiate \"\" on each side with respect to \"\".

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\"\"

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\"\"

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Find the critical points.

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Equate \"\" to zero:

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\"\"

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\"\" and \"\"

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\"\" and \"\"

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The critical points are \"\" and \"\".

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The test intervals are \"\"\"\" and \"\".

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\"\"

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First derivative test :

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
IntervalTest ValueSign of \"\"Conclusion
\"\"\"\"\"\"Decreasing
\"\"\"\"\"\"Increasing
\"\"\"\"\"\"Decreasing
\

The function \"\" has a local minimum at \"\", because \"\" changes its sign from negative to positive.

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\"\"

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Local minimum is \"\".

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The function \"\" has a local maximum at \"\", because \"\" changes its sign from positive to negative.

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\"\"

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Local maximum is \"\".

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\"\"

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Second derivative test :

\

\"\".

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Differentiate \"\" on each side with respect to \"\".

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\"\"

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Substitute \"\" in second derivative.

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\"\"

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Since \"\", curve is concave up.

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Therefore local minimum at \"\".

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Local minimum is \"\".

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Substitute \"\" in second derivative.

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\"\"

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Since \"\", curve is concave down.

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Therefore local maximum at \"\".

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Local maximum is \"\".

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\"\"

\

Local maximum is \"\".

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Local minimum is \"\".