The function is .
Differentiate on each side with respect to
.
Find the critical points.
\Equate to zero:
and
and
The critical points are and
.
The test intervals are ,
and
.
First derivative test :
\Interval | \Test Value | \Sign of ![]() | \
Conclusion | \
![]() | \
![]() | \
![]() | \
Decreasing | \
![]() | \
![]() | \
![]() | \
Increasing | \
![]() | \
![]() | \
![]() | \
Decreasing | \
The function has a local minimum at
, because
changes its sign from negative to positive.
Local minimum is .
The function has a local maximum at
, because
changes its sign from positive to negative.
Local maximum is .
Second derivative test :
\.
Differentiate on each side with respect to
.
Substitute in second derivative.
Since , curve is concave up.
Therefore local minimum at .
Local minimum is .
Substitute in second derivative.
Since , curve is concave down.
Therefore local maximum at .
Local maximum is .
Local maximum is .
Local minimum is .