(a)
\The function is .
Differentiate on each side with respect to
.
Find the critical points.
\Since is a polynomial it is continuous at all the point.
Therefore the critical points exist when .
Equate to zero.
and
and
and
and
.
The critical points are ,
and
.
The test intervals are ,
,
and
.
Interval | \Test Value | \Sign of ![]() | \
Conclusion | \
![]() | \
![]() | \
\
| \
Decreasing | \
\
| \
![]() | \
\
| \
Increasing | \
![]() | \
![]() | \
\
| \
Increasing | \
![]() | \
![]() | \
\
| \
Decreasing | \
The function is increasing on the interval .
The function is decreasing on the intervals and
.
(b)
\Find the local maximum and local minimum.
\The function has a local minimum at
, because
changes its sign from negative to positive.
Substitute in
.
Local minimum is .
The function has a local maximum at
, because
changes its sign from positive to negative.
Substitute in
.
Local maximum is .
(c)
\.
Differentiate on each side with respect to
.
\
Find the inflection points.
\Equate to zero.
and
and
and
and
.
The inflection point are at ,
and
.
Substitute in
.
Substitute in
.
Substitute in
.
The test intervals are ,
,
and
.
\
Interval \ | \
Test Value | \Sign of ![]() | \
Concavity | \
![]() | \
![]() | \
\
| \
Up | \
![]() | \
![]() | \
\
| \
Down | \
![]() | \
![]() | \
\
| \
Up | \
![]() | \
![]() | \
\
| \
Down | \
The graph is concave up on the intervals and
.
The graph is concave down on the intervals and
.
The inflection points are ,
and
.
(d)
\Graph :
\Graph the function :
(a)
\Increasing on the interval.
Decreasing on the intervals and
.
(b)
\Local maximum is .
Local minimum is .
(c)
\Concave up in the intervals and
.
Concave down in the intervals and
.
Inflection points are ,
and
.
(d)
\Graph of the function is
.