\"\"

\

(a)

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The function is \"\".

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Differentiate \"\" on each side with respect to \"\".

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\"\"

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Find the critical points.

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Therefore the critical points exist when \"\".

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Equate \"\" to zero.

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\"\"

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The critical point is \"\".

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The domain of \"\" is \"\".

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The test intervals are \"\" and \"\".

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
IntervalTest ValueSign of \"\"Conclusion
\"\"\"\" \

\"\"

\
Decreasing
\"\"\"\" \

\"\"

\
Increasing
\

The function is increasing on the interval \"\".

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The function is decreasing on the interval \"\".

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\"\"

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(b)

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Find the local maximum and local minimum.

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The function \"\" has a local minimum at \"\", because \"\" changes its sign from negative to positive.

\

Substitute \"\" in \"\".

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\"\"

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Local minimum is \"\".

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\"\"

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(c)

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\"\".

\

Differentiate \"\" on each side with respect to \"\".

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\"\" 

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Find the inflection points.

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Equate \"\" to zero.

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\"\"

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There is no inflection point, since \"\" is not in the domain.

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The test interval is\"\".

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
\

Interval

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Test ValueSign of \"\"Concavity
\"\"\"\" \

\"\"

\
Up
\

The graph is concave up on the interval \"\".

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\"\"

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(d)

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Graph :

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Graph the function \"\" :

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\"\"

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\"\"

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(a)

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Increasing on the interval \"\".

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Decreasing on the interval \"\".

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(b)

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Local minimum is \"\".

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(c)

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Concave up in the interval \"\".

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There is no inflection point.

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(d)

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Graph of the function \"\" is

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\"\"