\
The function is .
(A)
\Domain :
\The function is .
All possible values of is the domain of the function.
Denominator of the function should not be zero
\The domain of the function is
.
\
(B)
\Intercepts :
\To find the -intercepts, substitute
in the function.
.
Therefore the -intercept is
.
To find the -intercepts, substitute
in the function.
Therefore the -intercept is
.
\
(C)
\Symmetry :
\Substitute in the function.
.
Hence .
Therefore the function is an odd function.
\
(D)
\Asymptotes :
\Horizontal asymptote :
\
Therefore the horizontal asymptote is .
Vertical asymptote :
\Vertical asymptote appears when the function is not defined.
\Therefore the vertical asymptote are and
.
\
(E)
\Intervals of increase or decrease :
\The function is .
Differentiate on each side with respect to .
is never zero and the function is negative for the domain of
.
Therefore is decreasing over its domain.
\
(F)
\Local Maximum and Minimum values :
\From (E) it is clear that the function is only decreasing.
\Therefore is no local minimum or maximum values.
\\
(G)
\Concavity and point of inflection :
\.
Differentiate on each side with respect to
.
\
Find inflection point by equating to zero.
Inflection point is.
But at and
, the function is undefined,hence consider those points also.
Split the intervals into ,
,
and
.
\
Interval \ | \
Test Value | \Sign of ![]() | \
Concavity | \
![]() | \
![]() | \
\
| \
Down | \
![]() | \
![]() | \
\
| \
\
\ Up \ | \
![]() | \
![]() | \
\
\ | \
Down | \
![]() | \
![]() | \
![]() | \
Up | \
The graph is concave up in the interval ,
.
The graph is concave down in the interval and
.
\
(H)
\Graph :
\Graph of the function :
\
(A) The domain of the function is
.
\
(B) -intercept is
and
-intercepts are
.
(C) No symmetry.
\(D) The horizontal asymptote is and the vertical asymptotes are
and
.
(E) Decreasing on ,
and
.
(F) There is neither local minimum nor local maximum.
\(G) Concave up on and
.
concave down on and
.
(H) Graph of the function is