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The integral is .
Here integrand function is and the interval is
.
Find the absolute minimum and maximum values in the interval .
.
Differentiate on each side with respect to .
.
Find the critical number by equating to zero.
Hence there is only one number in the interval .
Find the value of the function at the critical number .
Find the value of the function at the end points at .
Therefore, absolute minimum in the is
.
Absolute maximum in the is
.
.
Comparison property of integrals:
\If for
, then
.
Here and
.
Hence by the comparison property of integrals,
\
\
.